3[q-2]+2=5q-7-2q

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Solution for 3[q-2]+2=5q-7-2q equation:


Simplifying
3[q + -2] + 2 = 5q + -7 + -2q

Reorder the terms:
3[-2 + q] + 2 = 5q + -7 + -2q
[-2 * 3 + q * 3] + 2 = 5q + -7 + -2q
[-6 + 3q] + 2 = 5q + -7 + -2q

Reorder the terms:
-6 + 2 + 3q = 5q + -7 + -2q

Combine like terms: -6 + 2 = -4
-4 + 3q = 5q + -7 + -2q

Reorder the terms:
-4 + 3q = -7 + 5q + -2q

Combine like terms: 5q + -2q = 3q
-4 + 3q = -7 + 3q

Add '-3q' to each side of the equation.
-4 + 3q + -3q = -7 + 3q + -3q

Combine like terms: 3q + -3q = 0
-4 + 0 = -7 + 3q + -3q
-4 = -7 + 3q + -3q

Combine like terms: 3q + -3q = 0
-4 = -7 + 0
-4 = -7

Solving
-4 = -7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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